How Many Moles Are In 2.3 Grams Of Phosphorus

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Apr 07, 2025 · 5 min read

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How Many Moles Are in 2.3 Grams of Phosphorus? A Comprehensive Guide
Determining the number of moles in a given mass of a substance is a fundamental concept in chemistry. This guide will walk you through the process of calculating the number of moles in 2.3 grams of phosphorus, explaining the underlying principles and providing a step-by-step solution. We'll also delve into the different allotropes of phosphorus and their impact on the calculation.
Understanding Moles and Molar Mass
Before we begin the calculation, let's clarify some key concepts:
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Mole (mol): The mole is the International System of Units (SI) base unit for the amount of substance. It represents a specific number of particles, whether atoms, molecules, ions, or formula units. This number is Avogadro's number, approximately 6.022 x 10<sup>23</sup>.
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Molar Mass (g/mol): The molar mass of a substance is the mass of one mole of that substance. It's numerically equal to the atomic weight (for elements) or molecular weight (for compounds) expressed in grams per mole (g/mol).
Determining the Molar Mass of Phosphorus
Phosphorus exists in several allotropic forms, meaning it can exist in different structural modifications with varying properties. The most common forms are white phosphorus (P<sub>4</sub>) and red phosphorus. The molar mass we use depends on which allotrope we're considering.
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White Phosphorus (P<sub>4</sub>): White phosphorus is a highly reactive and toxic allotrope consisting of P<sub>4</sub> molecules. The molar mass of P<sub>4</sub> is calculated by multiplying the atomic mass of phosphorus (approximately 30.97 g/mol) by 4:
4 * 30.97 g/mol = 123.88 g/mol
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Red Phosphorus: Red phosphorus is a less reactive allotrope with a polymeric structure. While the exact structure is complex, for the purpose of molar mass calculation, we typically consider it as consisting of individual phosphorus atoms (P). Therefore, the molar mass of red phosphorus is approximately 30.97 g/mol.
Since the problem doesn't specify the allotropic form, we'll calculate the number of moles for both white and red phosphorus.
Calculating Moles for White Phosphorus
To calculate the number of moles in 2.3 grams of white phosphorus (P<sub>4</sub>), we use the following formula:
Moles = Mass (g) / Molar Mass (g/mol)
Plugging in the values:
Moles = 2.3 g / 123.88 g/mol
Moles ≈ 0.0185 moles of P<sub>4</sub>
This means there are approximately 0.0185 moles of P<sub>4</sub> molecules in 2.3 grams of white phosphorus. To find the number of individual phosphorus atoms, we multiply by 4 (since there are 4 atoms per molecule):
0.0185 moles * 4 atoms/mol ≈ 0.074 moles of P atoms
Calculating Moles for Red Phosphorus
For red phosphorus, the calculation is simpler because we use the atomic mass directly:
Moles = 2.3 g / 30.97 g/mol
Moles ≈ 0.074 moles of P
This indicates that there are approximately 0.074 moles of phosphorus atoms in 2.3 grams of red phosphorus.
Understanding the Difference in Results
The difference in the results stems from the different molar masses associated with the different allotropic forms of phosphorus. White phosphorus, with its P<sub>4</sub> molecules, has a significantly higher molar mass than red phosphorus, which is considered to consist of individual P atoms for molar mass calculations. This results in a lower number of moles for white phosphorus compared to red phosphorus when considering the same mass (2.3 grams).
Practical Applications and Significance
The ability to accurately determine the number of moles in a given mass of a substance is crucial in various chemical contexts:
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Stoichiometry: Stoichiometric calculations rely heavily on mole relationships to determine the quantities of reactants and products in chemical reactions.
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Solution Preparation: Preparing solutions of a specific concentration requires precise knowledge of the number of moles of solute.
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Titrations: Titration calculations involve determining the concentration of a solution by reacting it with a solution of known concentration, requiring accurate mole calculations.
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Analytical Chemistry: Many analytical techniques, such as spectroscopy and chromatography, require the precise measurement of the amount of substance, often expressed in moles.
Factors Affecting Accuracy
The accuracy of the mole calculation depends on several factors:
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Purity of Phosphorus: The purity of the phosphorus sample will affect the accuracy of the mass measurement, leading to errors in the final mole calculation. Impurities will contribute to the overall mass but not to the number of phosphorus atoms or molecules.
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Precision of Measurement: The precision of the balance used to measure the mass of phosphorus is crucial. A more precise balance will yield a more accurate result.
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Accurate Atomic Mass: The atomic mass of phosphorus used in the calculation should be accurate to the number of significant figures used in the mass measurement.
Conclusion
Calculating the number of moles in 2.3 grams of phosphorus depends critically on knowing the allotropic form of the phosphorus. For white phosphorus (P<sub>4</sub>), we found approximately 0.0185 moles of P<sub>4</sub> molecules, or 0.074 moles of individual phosphorus atoms. For red phosphorus (P), we found approximately 0.074 moles of phosphorus atoms. This calculation highlights the importance of understanding molar mass and the significance of specifying the allotropic form when working with elements that exhibit allotropy. Accurate mole calculations are fundamental to many chemical calculations and processes. Remember to always consider the factors affecting accuracy to ensure reliable results in your chemical work.
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